Resistances in Series When some conductors having resistances R 1 , R 2 , and R 3 etc. are joined end on end as in figure below they are said to be connected in series. It can be proved that the equivalent resistance or total resistance between points A and D is equal to the sum of the three individual resistances. Being a series circuit, it should be kept in mind that figure 1 figure 2 (i) current is the same through all three conductors (I = I 1 = I 2 = I 3 ) (ii) voltage drop across each is different due to Its resistance and is given by Ohm's Law (iii) sum of the three voltage drops is equal to the voltage applied across the three conductors. There is a progressive fall in potential as we go from point A to D as shown in Figure 3 figure 3 V = V 1 + V 2 + V 3 = IR 1 + IR 2 + IR 3 But V = IR where R is the equivalent resistance of the series combination. IR=IR 1 + IR 2 + IR 3 R eq =R 1 +R 2 +R 3 Resistances in Parallel Three resistances, as joined i...
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